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Specific Heat Capacity

cal/(kg·°C)toBTU/(lb·°F)

Convert calories per kilogram-Celsius (cal/(kg·°C)) to BTUs per pound-Fahrenheit (BTU/(lb·°F)).

Factor1 cal/(kg·°C) = 0.0009993312 BTU/(lb·°F)

Converter

cal/(kg·°C)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
0.000999331BTU/(lb·°F)

Rendered to 6 significant figures.

Formula

Formula
BTU/(lb·°F) = cal/(kg·°C) × 0.0009993312

Multiply any value in calories per kilogram-Celsius by 0.0009993312 to obtain the value in BTUs per pound-Fahrenheit.

Worked example

Convert 1 cal/(kg·°C) to BTU/(lb·°F).

  1. 01Start with 1 cal/(kg·°C).
  2. 02Multiply by the conversion factor: 1 × 0.0009993312 = 0.000999331 BTU/(lb·°F).
Result1 cal/(kg·°C) = 0.000999331 BTU/(lb·°F)

Conversion table

cal/(kg·°C)BTU/(lb·°F)
10.00099933
20.0019987
50.0049967
100.0099933
200.019987
500.049967
1000.099933
2000.19987
5000.49967
10000.99933

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from cal/(kg·°C) to BTU/(lb·°F)?
1 cal/(kg·°C) equals 0.0009993312 BTU/(lb·°F). To convert, multiply the value in calories per kilogram-Celsius by 0.0009993312.
How do I convert 1 cal/(kg·°C) to BTU/(lb·°F)?
1 cal/(kg·°C) = 0.000999331 BTU/(lb·°F). For any value, multiply by 0.0009993312.
How do I convert BTU/(lb·°F) back to cal/(kg·°C)?
Divide by the same factor — or equivalently, multiply by 1000.669. So 1 BTU/(lb·°F) = 1000.67 cal/(kg·°C).
When would I need to convert calorie per kilogram-Celsius to BTU per pound-Fahrenheit?
Specific-heat-capacity conversions between cal/(kg·°C) and BTU/(lb·°F) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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