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Specific Heat Capacity

cal/(kg·°C)toJ/(kg·K)

Convert calories per kilogram-Celsius (cal/(kg·°C)) to joules per kilogram-kelvin (J/(kg·K)).

Factor1 cal/(kg·°C) = 4.184 J/(kg·K)

Converter

cal/(kg·°C)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
4.184J/(kg·K)

Rendered to 6 significant figures.

Formula

Formula
J/(kg·K) = cal/(kg·°C) × 4.184

Multiply any value in calories per kilogram-Celsius by 4.184 to obtain the value in joules per kilogram-kelvin.

Worked example

Convert 1 cal/(kg·°C) to J/(kg·K).

  1. 01Start with 1 cal/(kg·°C).
  2. 02Multiply by the conversion factor: 1 × 4.184 = 4.184 J/(kg·K).
Result1 cal/(kg·°C) = 4.184 J/(kg·K)

Conversion table

cal/(kg·°C)J/(kg·K)
14.184
28.368
520.92
1041.84
2083.68
50209.2
100418.4
200836.8
5002092
10004184

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from cal/(kg·°C) to J/(kg·K)?
1 cal/(kg·°C) equals 4.184 J/(kg·K). To convert, multiply the value in calories per kilogram-Celsius by 4.184.
How do I convert 1 cal/(kg·°C) to J/(kg·K)?
1 cal/(kg·°C) = 4.184 J/(kg·K). For any value, multiply by 4.184.
How do I convert J/(kg·K) back to cal/(kg·°C)?
Divide by the same factor — or equivalently, multiply by 0.2390057. So 1 J/(kg·K) = 0.239006 cal/(kg·°C).
When would I need to convert calorie per kilogram-Celsius to joule per kilogram-kelvin?
Specific-heat-capacity conversions between cal/(kg·°C) and J/(kg·K) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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