Specific Heat Capacity
BTU/(lb·°F)tocal/(kg·°C)
Convert BTUs per pound-Fahrenheit (BTU/(lb·°F)) to calories per kilogram-Celsius (cal/(kg·°C)).
Factor1 BTU/(lb·°F) = 1000.669 cal/(kg·°C)
Converter
BTU/(lb·°F)
Accepts numbers or expressions, e.g. 150 + 14.7
Result
cal/(kg·°C)
Rendered to 6 significant figures.
Formula
Formula
cal/(kg·°C) = BTU/(lb·°F) × 1000.669
Multiply any value in BTUs per pound-Fahrenheit by 1000.669 to obtain the value in calories per kilogram-Celsius.
Worked example
Convert 1 BTU/(lb·°F) to cal/(kg·°C).
- 01Start with 1 BTU/(lb·°F).
- 02Multiply by the conversion factor: 1 × 1000.669 = 1000.67 cal/(kg·°C).
Result1 BTU/(lb·°F) = 1000.67 cal/(kg·°C)
Conversion table
| BTU/(lb·°F) | cal/(kg·°C) |
|---|---|
| 1 | 1000.7 |
| 2 | 2001.3 |
| 5 | 5003.3 |
| 10 | 10007 |
| 20 | 20013 |
| 50 | 50033 |
| 100 | 1.0007e+5 |
| 200 | 2.0013e+5 |
| 500 | 5.0033e+5 |
| 1000 | 1.0007e+6 |
Reference values rounded to 5 significant figures for display.
FAQ
What is the conversion factor from BTU/(lb·°F) to cal/(kg·°C)?
1 BTU/(lb·°F) equals 1000.669 cal/(kg·°C). To convert, multiply the value in BTUs per pound-Fahrenheit by 1000.669.
How do I convert 1 BTU/(lb·°F) to cal/(kg·°C)?
1 BTU/(lb·°F) = 1000.67 cal/(kg·°C). For any value, multiply by 1000.669.
How do I convert cal/(kg·°C) back to BTU/(lb·°F)?
Divide by the same factor — or equivalently, multiply by 0.0009993312. So 1 cal/(kg·°C) = 0.000999331 BTU/(lb·°F).
When would I need to convert BTU per pound-Fahrenheit to calorie per kilogram-Celsius?
Specific-heat-capacity conversions between BTU/(lb·°F) and cal/(kg·°C) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).
Related conversions
- cal/(kg·°C) → BTU/(lb·°F)calorie per kilogram-Celsius → BTU per pound-Fahrenheit
- J/(kg·K) → BTU/(lb·°F)joule per kilogram-kelvin → BTU per pound-Fahrenheit
- BTU/(lb·°F) → J/(kg·K)BTU per pound-Fahrenheit → joule per kilogram-kelvin
- J/(kg·K) → cal/(kg·°C)joule per kilogram-kelvin → calorie per kilogram-Celsius
- cal/(kg·°C) → J/(kg·K)calorie per kilogram-Celsius → joule per kilogram-kelvin
- kJ/(kg·K) → BTU/(lb·°F)kilojoule per kilogram-kelvin → BTU per pound-Fahrenheit