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Specific Heat Capacity

BTU/(lb·°F)toJ/(kg·K)

Convert BTUs per pound-Fahrenheit (BTU/(lb·°F)) to joules per kilogram-kelvin (J/(kg·K)).

Factor1 BTU/(lb·°F) = 4186.8 J/(kg·K)

Converter

BTU/(lb·°F)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
4186.8J/(kg·K)

Rendered to 6 significant figures.

Formula

Formula
J/(kg·K) = BTU/(lb·°F) × 4186.8

Multiply any value in BTUs per pound-Fahrenheit by 4186.8 to obtain the value in joules per kilogram-kelvin.

Worked example

Convert 1 BTU/(lb·°F) to J/(kg·K).

  1. 01Start with 1 BTU/(lb·°F).
  2. 02Multiply by the conversion factor: 1 × 4186.8 = 4186.8 J/(kg·K).
Result1 BTU/(lb·°F) = 4186.8 J/(kg·K)

Conversion table

BTU/(lb·°F)J/(kg·K)
14186.8
28373.6
520934
1041868
2083736
502.0934e+5
1004.1868e+5
2008.3736e+5
5002.0934e+6
10004.1868e+6

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from BTU/(lb·°F) to J/(kg·K)?
1 BTU/(lb·°F) equals 4186.8 J/(kg·K). To convert, multiply the value in BTUs per pound-Fahrenheit by 4186.8.
How do I convert 1 BTU/(lb·°F) to J/(kg·K)?
1 BTU/(lb·°F) = 4186.8 J/(kg·K). For any value, multiply by 4186.8.
How do I convert J/(kg·K) back to BTU/(lb·°F)?
Divide by the same factor — or equivalently, multiply by 0.0002388459. So 1 J/(kg·K) = 0.000238846 BTU/(lb·°F).
When would I need to convert BTU per pound-Fahrenheit to joule per kilogram-kelvin?
Specific-heat-capacity conversions between BTU/(lb·°F) and J/(kg·K) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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