Specific Heat Capacity
kJ/(kg·K)tocal/(kg·°C)
Convert kilojoules per kilogram-kelvin (kJ/(kg·K)) to calories per kilogram-Celsius (cal/(kg·°C)).
Factor1 kJ/(kg·K) = 239.0057 cal/(kg·°C)
Converter
kJ/(kg·K)
Accepts numbers or expressions, e.g. 150 + 14.7
Result
cal/(kg·°C)
Rendered to 6 significant figures.
Formula
Formula
cal/(kg·°C) = kJ/(kg·K) × 239.0057
Multiply any value in kilojoules per kilogram-kelvin by 239.0057 to obtain the value in calories per kilogram-Celsius.
Worked example
Convert 4.184 kJ/(kg·K) to cal/(kg·°C).
- 01Start with 4.184 kJ/(kg·K).
- 02Multiply by the conversion factor: 4.184 × 239.0057 = 1000 cal/(kg·°C).
Result4.184 kJ/(kg·K) = 1000 cal/(kg·°C)
Conversion table
| kJ/(kg·K) | cal/(kg·°C) |
|---|---|
| 1 | 239.01 |
| 2 | 478.01 |
| 5 | 1195 |
| 10 | 2390.1 |
| 20 | 4780.1 |
| 50 | 11950 |
| 100 | 23901 |
| 200 | 47801 |
| 500 | 1.1950e+5 |
| 1000 | 2.3901e+5 |
Reference values rounded to 5 significant figures for display.
FAQ
What is the conversion factor from kJ/(kg·K) to cal/(kg·°C)?
1 kJ/(kg·K) equals 239.0057 cal/(kg·°C). To convert, multiply the value in kilojoules per kilogram-kelvin by 239.0057.
How do I convert 1 kJ/(kg·K) to cal/(kg·°C)?
1 kJ/(kg·K) = 239.006 cal/(kg·°C). For any value, multiply by 239.0057.
How do I convert cal/(kg·°C) back to kJ/(kg·K)?
Divide by the same factor — or equivalently, multiply by 0.004184. So 1 cal/(kg·°C) = 0.004184 kJ/(kg·K).
When would I need to convert kilojoule per kilogram-kelvin to calorie per kilogram-Celsius?
Specific-heat-capacity conversions between kJ/(kg·K) and cal/(kg·°C) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).
Related conversions
- cal/(kg·°C) → kJ/(kg·K)calorie per kilogram-Celsius → kilojoule per kilogram-kelvin
- J/(kg·K) → kJ/(kg·K)joule per kilogram-kelvin → kilojoule per kilogram-kelvin
- kJ/(kg·K) → J/(kg·K)kilojoule per kilogram-kelvin → joule per kilogram-kelvin
- J/(kg·K) → cal/(kg·°C)joule per kilogram-kelvin → calorie per kilogram-Celsius
- cal/(kg·°C) → J/(kg·K)calorie per kilogram-Celsius → joule per kilogram-kelvin
- kJ/(kg·K) → J/(g·K)kilojoule per kilogram-kelvin → joule per gram-kelvin