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Specific Heat Capacity

J/(kg·K)tocal/(g·°C)

Convert joules per kilogram-kelvin (J/(kg·K)) to calories per gram-Celsius (cal/(g·°C)).

Factor1 J/(kg·K) = 0.0002390057 cal/(g·°C)

Converter

J/(kg·K)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
1cal/(g·°C)

Rendered to 6 significant figures.

Formula

Formula
cal/(g·°C) = J/(kg·K) × 0.0002390057

Multiply any value in joules per kilogram-kelvin by 0.0002390057 to obtain the value in calories per gram-Celsius.

Worked example

Convert 4184 J/(kg·K) to cal/(g·°C).

  1. 01Start with 4184 J/(kg·K).
  2. 02Multiply by the conversion factor: 4184 × 0.0002390057 = 1 cal/(g·°C).
Result4184 J/(kg·K) = 1 cal/(g·°C)

Conversion table

J/(kg·K)cal/(g·°C)
10.00023901
20.00047801
50.001195
100.0023901
200.0047801
500.01195
1000.023901
2000.047801
5000.1195
10000.23901

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from J/(kg·K) to cal/(g·°C)?
1 J/(kg·K) equals 0.0002390057 cal/(g·°C). To convert, multiply the value in joules per kilogram-kelvin by 0.0002390057.
How do I convert 1 J/(kg·K) to cal/(g·°C)?
1 J/(kg·K) = 0.000239006 cal/(g·°C). For any value, multiply by 0.0002390057.
How do I convert cal/(g·°C) back to J/(kg·K)?
Divide by the same factor — or equivalently, multiply by 4184. So 1 cal/(g·°C) = 4184 J/(kg·K).
When would I need to convert joule per kilogram-kelvin to calorie per gram-Celsius?
Specific-heat-capacity conversions between J/(kg·K) and cal/(g·°C) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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