Specific Heat Capacity
cal/(g·°C)toJ/(g·K)
Convert calories per gram-Celsius (cal/(g·°C)) to joules per gram-kelvin (J/(g·K)).
Factor1 cal/(g·°C) = 4.184 J/(g·K)
Converter
cal/(g·°C)
Accepts numbers or expressions, e.g. 150 + 14.7
Result
J/(g·K)
Rendered to 6 significant figures.
Formula
Formula
J/(g·K) = cal/(g·°C) × 4.184
Multiply any value in calories per gram-Celsius by 4.184 to obtain the value in joules per gram-kelvin.
Worked example
Convert 1 cal/(g·°C) to J/(g·K).
- 01Start with 1 cal/(g·°C).
- 02Multiply by the conversion factor: 1 × 4.184 = 4.184 J/(g·K).
Result1 cal/(g·°C) = 4.184 J/(g·K)
Conversion table
| cal/(g·°C) | J/(g·K) |
|---|---|
| 1 | 4.184 |
| 2 | 8.368 |
| 5 | 20.92 |
| 10 | 41.84 |
| 20 | 83.68 |
| 50 | 209.2 |
| 100 | 418.4 |
| 200 | 836.8 |
| 500 | 2092 |
| 1000 | 4184 |
Reference values rounded to 5 significant figures for display.
FAQ
What is the conversion factor from cal/(g·°C) to J/(g·K)?
1 cal/(g·°C) equals 4.184 J/(g·K). To convert, multiply the value in calories per gram-Celsius by 4.184.
How do I convert 1 cal/(g·°C) to J/(g·K)?
1 cal/(g·°C) = 4.184 J/(g·K). For any value, multiply by 4.184.
How do I convert J/(g·K) back to cal/(g·°C)?
Divide by the same factor — or equivalently, multiply by 0.2390057. So 1 J/(g·K) = 0.239006 cal/(g·°C).
When would I need to convert calorie per gram-Celsius to joule per gram-kelvin?
Specific-heat-capacity conversions between cal/(g·°C) and J/(g·K) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).
Related conversions
- J/(g·K) → cal/(g·°C)joule per gram-kelvin → calorie per gram-Celsius
- J/(kg·K) → J/(g·K)joule per kilogram-kelvin → joule per gram-kelvin
- J/(g·K) → J/(kg·K)joule per gram-kelvin → joule per kilogram-kelvin
- J/(kg·K) → cal/(g·°C)joule per kilogram-kelvin → calorie per gram-Celsius
- cal/(g·°C) → J/(kg·K)calorie per gram-Celsius → joule per kilogram-kelvin
- kJ/(kg·K) → J/(g·K)kilojoule per kilogram-kelvin → joule per gram-kelvin