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Specific Heat Capacity

BTU/(lb·°F)tokcal/(kg·°C)

Convert BTUs per pound-Fahrenheit (BTU/(lb·°F)) to kilocalories per kilogram-Celsius (kcal/(kg·°C)).

Factor1 BTU/(lb·°F) = 1.000669 kcal/(kg·°C)

Converter

BTU/(lb·°F)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
1.00067kcal/(kg·°C)

Rendered to 6 significant figures.

Formula

Formula
kcal/(kg·°C) = BTU/(lb·°F) × 1.000669

Multiply any value in BTUs per pound-Fahrenheit by 1.000669 to obtain the value in kilocalories per kilogram-Celsius.

Worked example

Convert 1 BTU/(lb·°F) to kcal/(kg·°C).

  1. 01Start with 1 BTU/(lb·°F).
  2. 02Multiply by the conversion factor: 1 × 1.000669 = 1.00067 kcal/(kg·°C).
Result1 BTU/(lb·°F) = 1.00067 kcal/(kg·°C)

Conversion table

BTU/(lb·°F)kcal/(kg·°C)
11.0007
22.0013
55.0033
1010.007
2020.013
5050.033
100100.07
200200.13
500500.33
10001000.7

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from BTU/(lb·°F) to kcal/(kg·°C)?
1 BTU/(lb·°F) equals 1.000669 kcal/(kg·°C). To convert, multiply the value in BTUs per pound-Fahrenheit by 1.000669.
How do I convert 1 BTU/(lb·°F) to kcal/(kg·°C)?
1 BTU/(lb·°F) = 1.00067 kcal/(kg·°C). For any value, multiply by 1.000669.
How do I convert kcal/(kg·°C) back to BTU/(lb·°F)?
Divide by the same factor — or equivalently, multiply by 0.9993312. So 1 kcal/(kg·°C) = 0.999331 BTU/(lb·°F).
When would I need to convert BTU per pound-Fahrenheit to kilocalorie per kilogram-Celsius?
Specific-heat-capacity conversions between BTU/(lb·°F) and kcal/(kg·°C) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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