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Heat Transfer

cal/(cm·s·°C)toW/(cm·K)

Convert calories per centimetre-second-Celsius (cal/(cm·s·°C)) to watts per centimetre-kelvin (W/(cm·K)).

Factor1 cal/(cm·s·°C) = 4.184 W/(cm·K)

Converter

cal/(cm·s·°C)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
4.184W/(cm·K)

Rendered to 6 significant figures.

Formula

Formula
W/(cm·K) = cal/(cm·s·°C) × 4.184

Multiply any value in calories per centimetre-second-Celsius by 4.184 to obtain the value in watts per centimetre-kelvin.

Worked example

Convert 1 cal/(cm·s·°C) to W/(cm·K).

  1. 01Start with 1 cal/(cm·s·°C).
  2. 02Multiply by the conversion factor: 1 × 4.184 = 4.184 W/(cm·K).
Result1 cal/(cm·s·°C) = 4.184 W/(cm·K)

Conversion table

cal/(cm·s·°C)W/(cm·K)
14.184
28.368
520.92
1041.84
2083.68
50209.2
100418.4
200836.8
5002092
10004184

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from cal/(cm·s·°C) to W/(cm·K)?
1 cal/(cm·s·°C) equals 4.184 W/(cm·K). To convert, multiply the value in calories per centimetre-second-Celsius by 4.184.
How do I convert 1 cal/(cm·s·°C) to W/(cm·K)?
1 cal/(cm·s·°C) = 4.184 W/(cm·K). For any value, multiply by 4.184.
How do I convert W/(cm·K) back to cal/(cm·s·°C)?
Divide by the same factor — or equivalently, multiply by 0.2390057. So 1 W/(cm·K) = 0.239006 cal/(cm·s·°C).
When would I need to convert calorie per centimetre-second-Celsius to watt per centimetre-kelvin?
Thermal conductivity conversions between cal/(cm·s·°C) and W/(cm·K) are common in insulation specification, heat-exchanger design, and building-envelope analysis. SI units (W/(m·K)) appear in international standards and simulation tools, while BTU/(hr·ft·°F) is standard in US codes and vendor datasheets.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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