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Heat Transfer

cal/(cm·s·°C)toW/(m·K)

Convert calories per centimetre-second-Celsius (cal/(cm·s·°C)) to watts per metre-kelvin (W/(m·K)).

Factor1 cal/(cm·s·°C) = 418.4 W/(m·K)

Converter

cal/(cm·s·°C)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
418.4W/(m·K)

Rendered to 6 significant figures.

Formula

Formula
W/(m·K) = cal/(cm·s·°C) × 418.4

Multiply any value in calories per centimetre-second-Celsius by 418.4 to obtain the value in watts per metre-kelvin.

Worked example

Convert 1 cal/(cm·s·°C) to W/(m·K).

  1. 01Start with 1 cal/(cm·s·°C).
  2. 02Multiply by the conversion factor: 1 × 418.4 = 418.4 W/(m·K).
Result1 cal/(cm·s·°C) = 418.4 W/(m·K)

Conversion table

cal/(cm·s·°C)W/(m·K)
1418.4
2836.8
52092
104184
208368
5020920
10041840
20083680
5002.0920e+5
10004.1840e+5

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from cal/(cm·s·°C) to W/(m·K)?
1 cal/(cm·s·°C) equals 418.4 W/(m·K). To convert, multiply the value in calories per centimetre-second-Celsius by 418.4.
How do I convert 1 cal/(cm·s·°C) to W/(m·K)?
1 cal/(cm·s·°C) = 418.4 W/(m·K). For any value, multiply by 418.4.
How do I convert W/(m·K) back to cal/(cm·s·°C)?
Divide by the same factor — or equivalently, multiply by 0.002390057. So 1 W/(m·K) = 0.00239006 cal/(cm·s·°C).
When would I need to convert calorie per centimetre-second-Celsius to watt per metre-kelvin?
Thermal conductivity conversions between cal/(cm·s·°C) and W/(m·K) are common in insulation specification, heat-exchanger design, and building-envelope analysis. SI units (W/(m·K)) appear in international standards and simulation tools, while BTU/(hr·ft·°F) is standard in US codes and vendor datasheets.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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