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Specific Heat Capacity

J/(kg·°C)tokcal/(kg·°C)

Convert joules per kilogram-Celsius (J/(kg·°C)) to kilocalories per kilogram-Celsius (kcal/(kg·°C)).

Factor1 J/(kg·°C) = 0.0002390057 kcal/(kg·°C)

Converter

J/(kg·°C)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
1kcal/(kg·°C)

Rendered to 6 significant figures.

Formula

Formula
kcal/(kg·°C) = J/(kg·°C) × 0.0002390057

Multiply any value in joules per kilogram-Celsius by 0.0002390057 to obtain the value in kilocalories per kilogram-Celsius.

Worked example

Convert 4184 J/(kg·°C) to kcal/(kg·°C).

  1. 01Start with 4184 J/(kg·°C).
  2. 02Multiply by the conversion factor: 4184 × 0.0002390057 = 1 kcal/(kg·°C).
Result4184 J/(kg·°C) = 1 kcal/(kg·°C)

Conversion table

J/(kg·°C)kcal/(kg·°C)
10.00023901
20.00047801
50.001195
100.0023901
200.0047801
500.01195
1000.023901
2000.047801
5000.1195
10000.23901

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from J/(kg·°C) to kcal/(kg·°C)?
1 J/(kg·°C) equals 0.0002390057 kcal/(kg·°C). To convert, multiply the value in joules per kilogram-Celsius by 0.0002390057.
How do I convert 1 J/(kg·°C) to kcal/(kg·°C)?
1 J/(kg·°C) = 0.000239006 kcal/(kg·°C). For any value, multiply by 0.0002390057.
How do I convert kcal/(kg·°C) back to J/(kg·°C)?
Divide by the same factor — or equivalently, multiply by 4184. So 1 kcal/(kg·°C) = 4184 J/(kg·°C).
When would I need to convert joule per kilogram-Celsius to kilocalorie per kilogram-Celsius?
Specific-heat-capacity conversions between J/(kg·°C) and kcal/(kg·°C) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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