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Specific Heat Capacity

BTU/(lb·°R)tokJ/(kg·K)

Convert BTUs per pound-Rankine (BTU/(lb·°R)) to kilojoules per kilogram-kelvin (kJ/(kg·K)).

Factor1 BTU/(lb·°R) = 4.1868 kJ/(kg·K)

Converter

BTU/(lb·°R)

Accepts numbers or expressions, e.g. 150 + 14.7

Result
4.1868kJ/(kg·K)

Rendered to 6 significant figures.

Formula

Formula
kJ/(kg·K) = BTU/(lb·°R) × 4.1868

Multiply any value in BTUs per pound-Rankine by 4.1868 to obtain the value in kilojoules per kilogram-kelvin.

Worked example

Convert 1 BTU/(lb·°R) to kJ/(kg·K).

  1. 01Start with 1 BTU/(lb·°R).
  2. 02Multiply by the conversion factor: 1 × 4.1868 = 4.1868 kJ/(kg·K).
Result1 BTU/(lb·°R) = 4.1868 kJ/(kg·K)

Conversion table

BTU/(lb·°R)kJ/(kg·K)
14.1868
28.3736
520.934
1041.868
2083.736
50209.34
100418.68
200837.36
5002093.4
10004186.8

Reference values rounded to 5 significant figures for display.

FAQ

What is the conversion factor from BTU/(lb·°R) to kJ/(kg·K)?
1 BTU/(lb·°R) equals 4.1868 kJ/(kg·K). To convert, multiply the value in BTUs per pound-Rankine by 4.1868.
How do I convert 1 BTU/(lb·°R) to kJ/(kg·K)?
1 BTU/(lb·°R) = 4.1868 kJ/(kg·K). For any value, multiply by 4.1868.
How do I convert kJ/(kg·K) back to BTU/(lb·°R)?
Divide by the same factor — or equivalently, multiply by 0.2388459. So 1 kJ/(kg·K) = 0.238846 BTU/(lb·°R).
When would I need to convert BTU per pound-Rankine to kilojoule per kilogram-kelvin?
Specific-heat-capacity conversions between BTU/(lb·°R) and kJ/(kg·K) are routine in thermal engineering, heat-balance work, HVAC design, metallurgy, chemical engineering and materials science. J/(kg·K) and kJ/(kg·K) are the SI standards; cal/(g·°C) is the classic thermochemical convention; BTU/(lb·°F) dominates US process and ASHRAE datasheets. All conversions use fixed multiplicative factors — this category does NOT look up the Cp value of any specific material (water, air, steam, etc.), does NOT perform heat-duty calculations (Q = m·Cp·ΔT), and does NOT convert lumped thermal capacity (J/K) to specific heat capacity (J/(kg·K)) without mass. Temperature units in the denominator represent temperature intervals, not absolute temperatures — a 1 °C interval equals a 1 K interval.
Is the conversion exact?
The factor shown is precise to at least 7 significant figures. For most process-engineering work this is far better than instrument accuracy. For metrology or trade applications, refer to the relevant national standard (NIST, BIPM, ISO 80000).

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